Technology is more accurate because a table limits how many places you can use in a calculation. You need either a Z score table, a graphical calculator or some kind of soft well like excel, and there are two types of table or 2 functions that can do that for you, I prefer to use technology if they have not. It can be turned into words in a minute, so we can score. How do we find that object? We're going to need to convert this percentage into a Z score and then from a Z score. So it's above the mean because of a point where 90 percent of these students read slower and 10 percent read faster. How much time per minute does it take to say a single word? Is he looking at the book? There is a 90 percent increase here. A child is at 90 percent according to the information we are given.

I'm going to start by drawing our normal distribution, which means that I'm 126 words per minute standard deviation. The reading speeds of 6th graders are usually distributed. Where xi and yi are the individual data points, and x̄ and ȳ are the means of the x and y values, respectively.įirst, calculate the means of the x and y values:

You should see that the points roughly form a straight line, indicating that it is reasonable to assume a linear relationship between the number of weeks and the speed gain.ī) To fit a straight line to the data using the method of least squares, we need to find the slope (B1) and the y-intercept (B0) of the line. Plot these points on a graph with the number of weeks on the x-axis and the speed gain on the y-axis. |-ġ09 | (This data point seems to be an error, so we will ignore it) Number of weeks (x) | Speed gain words per minute (y)

A) First, we need to create a scatter plot with the given data points:

Graphpad student